गणित में निश्चित समाकल
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xy-समतल के ग्राफ f, x-अक्ष, तथा x = a और x = b रेखाओं से घिरे हुए क्षेत्र के क्षेत्रफल के बराबर होता है। (x-अक्ष के ऊपर का क्षेत्रफल धनात्मक लेते हैं जबकि x-अक्ष के नीचे का क्षेत्र ऋणात्मक)
परिमेय या अपरिमेय व्यंजकों वाले निश्चित समाकल
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![{\displaystyle \int _{0}^{a}{\frac {x^{m}dx}{x^{n}+a^{n}}}={\frac {\pi a^{m-n+1}}{n\sin[(m+1)\pi /n)]}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/61ad7781af05eba437e936744503decf001c8391)
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

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![{\displaystyle \int _{0}^{a}x^{m}(a^{n}-x^{n})^{p}\,dx={\frac {a^{m+1+np}\Gamma [(m+1)/n]\Gamma (p+1)}{n\Gamma [((m+1)/n)+p+1]}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/8822a32bedafee733abd15d33c7ab8661fde22df)
![{\displaystyle \int _{0}^{\infty }{\frac {x^{m}\,dx}{({x^{n}+a^{n})}^{r}}}={\frac {(-1)^{r-1}\pi a^{m+1-nr}\Gamma [(m+1)/n]}{n\sin[(m+1)\pi /n](r-1)!\Gamma [(m+1)/n-r+1]}}\ \,0<m+1<nr}](https://wikimedia.org/api/rest_v1/media/math/render/svg/6b7c436a9cd6746cf2bd9ff867604e80b2243e65)
त्रिकोणमितीय निश्चित समाकल













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



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





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





चरघातांकी फलनों वाले निश्चित समाकल









![{\displaystyle \int _{0}^{\infty }x^{m}e^{-ax^{2}}\ dx={\frac {\Gamma [(m+1)/2]}{2a^{(m+1)/2}}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/385556f3e899aa11a391a01b8266854f5b53c708)













लघुगणकीय फलनों वाले निश्चित समाकल




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हाइपरबोलिक फलनों वाले निश्चित समाकल



विविध
![{\displaystyle \int _{0}^{\infty }{\frac {f(ax)-f(bx)}{x}}\ dx=[{f(0)-f(\infty )}]\ln {\frac {b}{a}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/ee2857c676e3fea94db32011780187559fd612c9)
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